Fixed latex math problem

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Christian Risi 2025-11-20 18:50:24 +01:00
parent 934c08d4c0
commit 1a30dc6400

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@ -281,12 +281,12 @@ small value, usually in the order of $10^{-8}$
> instead of a vector. To make it easier to understand in matricial notation: > instead of a vector. To make it easier to understand in matricial notation:
> >
> $$ > $$
> \begin{aligned} \begin{aligned}
> \nabla L^{(k + 1)} &= \frac{d \, Loss^{(k)}}{d \, W^{(k)}} \\ \nabla L^{(k + 1)} &= \frac{d \, Loss^{(k)}}{d \, W^{(k)}} \\
> G^{(k + 1)} &= G^{(k)} +(\nabla L^{(k+1)}) ^2 \\ G^{(k + 1)} &= G^{(k)} +(\nabla L^{(k+1)}) ^2 \\
> W^{(k+1)} &= W^{(k)} - \eta \frac{\nabla L^{(k + 1)}} W^{(k+1)} &= W^{(k)} - \eta \frac{\nabla L^{(k + 1)}}
{\sqrt{G^{(k+1)} + \epsilon}} {\sqrt{G^{(k+1)} + \epsilon}}
> \end{aligned} \end{aligned}
> $$ > $$
> >
> In other words, compute the gradient and scale it for the sum of its squares > In other words, compute the gradient and scale it for the sum of its squares